Комментарии:
have a test today and this video helped a lot....
ОтветитьThank you...i appreciate yr effort for this
Ответитьthatnk so much dude !! life saver the night before the exam
ОтветитьBro in the P4 bit , why didn't you start with the question mark , you put the 0 from the 4th bit as it is from the binary code
ОтветитьThank you
Ответитьi cane here to learn but your voice is so addictive
ОтветитьWhat if the wrong bit is in a parity position, let's say 4th position? What is the original pre-Hamming code data transmitted then?
ОтветитьSimple but effective
Ответитьhelped me a lot. thnx =)
Ответитьu failed in the last example at p8 it must be 1110 as i think and as u solved the first one
Ответитьsome people starts the counting from the least significant bit while you do it from most significant bit, won't it affect the answer? and if so, which one is the more correct?
ОтветитьThis guy just saved me a couple hours of research!!
ОтветитьThank you very Much, sir 🤘✨✨✨✨
It really helped me a lot to get my question's answer ^_^
Clear explanation 👍✨
came across few video on similar problems. but i could only finally catch up with this one. Thanks!
ОтветитьI have wasted 2 hours to solve a question then i found your video and solved the question in just 1 minute
Thanks 👍👍
Thank you so much. Wish you the best.
Ответитьawh. finally someone who speaks human language!
ОтветитьEasiest Explanation ever
ОтветитьYou are the best!
Ответитьwould this work the same for odd parity?
ОтветитьWell explanation, you made it much clear now, but shouldn't we write down P values with the data bits as well? you did so with P4 but doesn't the same principle hold for the rest of the P values too?
ОтветитьClear, concise presentation and delivery. Everything I ever wanted from an educational video. Thank you :)
ОтветитьTHANK YOU SO MUCHHH
ОтветитьI did not understand when my teacher explained but this video made so much sense!
Ответитьthis is decoding right?
ОтветитьFinally understood it thanks man!
ОтветитьOne Question, what do I do if there is more than 1 Corrupted bit?
ОтветитьI didn't understand the part where you check and skip parts.why at the P8 we skipped the 8 beats instead of checking them first ?
Ответитьthank you so much. amazing teaching
Ответитьdude , u are unmatched istg , are u kidding me ?! in 4minuts i got it . i love you .
ОтветитьSophisticated made simple. 👑
ОтветитьVery good ❤❤❤
ОтветитьI have a question: Will this method be used for odd parity as well? Please reply anyone I have paper tomorrow
ОтветитьSir we want formula
for parity(p8)
Love you, you saved me
Ответитьbest explanation
ОтветитьAmazing
ОтветитьBRO YOU RE SO GOOD AT EXPLAINING THINGS <3
ОтветитьDoes this also work with less bits (8 bits for example)
Ответитьlove u bro watched this last night very simple
🥰🥰
Thanks
Ответитьthanks my guy much simpler method
ОтветитьGreat full sir 😢
ОтветитьWhy did you add a question mark? In every material I read you still count the parity bit
Ответитьthis is worldclass
Ответитьyou are my superhero, been staring at my question for over 2 says wondering how they decided that the 7th bit is the corrupted one, thank you
ОтветитьHam
Ответитьnah bro you cooked
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