Undetermined coefficients 1 | Second order differential equations | Khan Academy

THANK YOU!!!

Thanks Khan! Now I can do my coursework!

You cleaned up what my calc4 instructor couldn't explain in 2 fifty min lectures.

great help cheers!

thought it was homoGENous

Learned more in the last 22 videos of this playlist than I have all quarter of Diff EQ. Final in 5 days. Thanks buddy.

it hurts to listen to this because the pronunciation of homogeneous is either wrong or i'm just not used to the word. I keep thinking of homogenized milk....

why did you do a second order one? Why not a first order? I can't find much videos about First Order and Linear diff. equations...

Can anyone help me out? non-linear and second+ order are much harder

y''+y'-12y=e^3x
I tried to solve but i didn't got the answer

Why is the solution for the homogeneous equation included at all? I don't understnd how it affects the general solution to the non homogeneous equation if it equals zero.

Very helpful! I cannot believe how much easier this is than it looked like in most books! Thank you

Do you realize you used 15 variables in this video? Wow!

what if i get 0 = e^4x from my question what do i do now? help pls

I don't understand the last bit...surely if the most general solution of Y is equal to Yg+Yp then A cannot be equal to -1/2? Yg is 0; so the most general solution of Y is equal to Yp. Yp is -1/2e^2x....so the most general solution of Y=-1/2e^2x??

Do you have a video where you explain how to solve when the coefficients are not constants?

the problem i am trying to solve has 4e^t on the right hand side. When you derivate it, it is still 4e^t. My function is y''-y=4e^t. Following Sal's method, i got Ae^t-Ae^t=4e^t. Which simplifies to 0=4e^t. Which does not exist :(. I think Sal's method only when the right hand function is something else other than e^t. Like it has to be e^2t or something like he's got.

differentiate coefficient f(t)=sin 2πft with respect to t ..help me sir

I love you

Thanke u sooouch my precious teacher.

Ur a very creative man

Nice explanation

why is quality og this video so poor?

The particular solution match the form of the homogenous solution. Should it be multiplied by x to be Axe^2x ????Not Ae^2x

What happens when g(x) from the beginning is a value like 3?

enhance your writing on video
it is not clear at all.

this is where calculus goes for full super saiyan mode.

This channel is the main reason I'm keeping up with my Linear Algebra and Mechanics classes... my professors don't know what examples or proper explanations are.

I appreciate the help, i just get confused when you introduce to many letters to express some things.

It seems like all these linear algebra names are both so long so hard to read.

Unbelivable explaining ability, thanks from Italy.

I love you bro

Thank you for your dedication! From HongKong.

Love ya khan academy.
Wish i could say that to my teachers!

I laughed when he said there should be a short form and i was like oh right you can't say that no more

An 11 year old free video explains things better than university tutors which I pay for.

Thank you sir... really useful 😊

this video was made when I was 8, and here I am in 2020 paying thousands to try and learn from a professor that cant teach, falling back to Khan Academy where it's easily taught and free.
thank you

This guy always sounds like he’s unveiling an evil plan at the start of his vids lol

This video Made 12 years ago, and here i am to understanding Second ordes. You helped a Lot of people. Thanks a lot sir🔥👍

Do we always need to predict what that so called j(x) will be......

As usual, Sal saved me.

this video is made when I was 6, and now I understand this better than how school taught us...

here u am in 2022, still learning from this video

You made it very easy to understand. Thank you so much sir 😊😊

Really Thankyou so much 🤧😭🙏🏻 these video r only my life saver....

thank you so much 😢

this video was uploaded when I was 4 and im now studying from this.. all the contents are as affective as it was before.

Thanks Sal :)

Thank you khan academy, y'all are really doing a great Job. Thank you for the years of consistency.

It's 2024 and the best resources available to learn Differential Equations are Sal's videos from 2007 and MIT's Differential Equation course from 2003. Both in 240p.