Комментарии:
Very neatly explained. Thank you
ОтветитьWhen you call the PassByReference(x); why are you able to pass in x and not the address of or reference of x. Such as PassByReference(&x); Because you declared your function to accept references. Thank you
Ответитьconst T& let you also pass rvalues of type T to the function otherwise we have to pass an lvalue
ОтветитьLooks like `const` is equivalent to `final` in Java
ОтветитьThank you
ОтветитьOne more👍!
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